Focus: Systems of Inequalities, Feasible Shaded Regions & Linear Programming Models
State the three linear inequalities that define the shaded region bounded by the lines $y = 2x + 1$, $x + y = 5$, and the $x$-axis in the first quadrant.
1. Below or on $y = 2x + 1$
2. Below or on $x + y = 5$
3. Above $x$-axis and in first quadrant
Determine whether each of the following points lies in the region defined by $3x - 2y < 8$:
(a) Point $(2, -1)$ [2 marks]
(b) Point $(4, 2)$ [2 marks]
(a) Substitute $(2, -1)$: $3(2) - 2(-1) = 6 + 2 = 8$. Since the inequality is strict ($<$), $8 < 8$ is False!
(b) Substitute $(4, 2)$: $3(4) - 2(2) = 12 - 4 = 8$. Again $8 < 8$ is False!
A manufacturer produces $x$ units of chair $A$ and $y$ units of chair $B$. Write an inequality for each of the following statements:
(i) The number of chairs $B$ produced is at most three times the number of chairs $A$. [2 marks]
(ii) The minimum total production of chairs is 120 units. [2 marks]
(i) "At most three times":
(ii) "Minimum 120 units":
A bakery bakes $x$ chocolate cakes and $y$ butter cakes daily. The daily baking is based on the following constraints:
(a) Write three linear inequalities, other than $x \ge 0$ and $y \ge 0$, representing the constraints. [4 marks]
(b) If the bakery bakes 60 butter cakes on a given day, determine the minimum and maximum number of chocolate cakes that can be baked. [3 marks]
(c) The profit from a chocolate cake is RM15 and from a butter cake is RM10. Calculate the maximum profit if 40 chocolate cakes are baked. [2 marks]
(a) Constraints:
(b) When $y = 60$:
(c) When $x = 40$:
A travel agency rents $x$ 40-seater buses and $y$ 25-seater vans to transport at least 300 passengers for an eco-tour:
(a) Write a system of four linear inequalities representing the constraints. [4 marks]
(b) If exactly 6 buses are rented, find the range of values for $y$ that satisfy all conditions. [3 marks]
(c) State the minimum cost to transport all 300 passengers. [2 marks]
(a) Inequalities:
(b) For $x = 6$:
(c) Minimum cost: $x = 8, y = 0 \implies 8(800) = \text{RM } 6,400$ (320 passengers $\ge 300$)